2v^2+15v+17=O

Solution for 2v^2+15v+17=O equation:

2v^2+15v+17=

We move all terms to the left:

2v^2+15v+17-()=0

We add all the numbers together, and all the variables

2v^2+15v=0

a = 2; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·2·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*2}=\frac{-30}{4}
=-7+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*2}=\frac{0}{4}
=0
$